移位运算图解：从原理到实战的深度解析

#include <stdio.h>
int main() {
    int a = 5;
    int b = -10;
    // 左移：5  2 = 10
    printf("5 << 1 = %d
", a << 1);
    // 右移：-10 / 2 = -5
    printf("-10 >> 1 = %d
", b >> 1);
    // 注意：C语言中无符号右移需使用 unsigned int
    unsigned int ub = (unsigned int)b;
    printf("-10 >>> 1 (unsigned) = %u
", ub >> 1);
    return 0;
}

public class BitShiftExample {
    public static void main(String[] args) {
        int a = 5;
        int b = -10;
        // 左移
        System.out.println("5 << 1 = " + (a << 1)); // 10
        // 有符号右移
        System.out.println("-10 >> 1 = " + (b >> 1)); // -5
        // 无符号右移
        System.out.println("-10 >>> 1 = " + (b >>> 1)); // 2147483643
    }
}

Python中的整数是任意精度的，因此移位行为略有不同
a = 5
b = -10
左移
print(f"5 << 1 = {a << 1}")  # 10
右移 (Python中 >> 总是保持符号)
print(f"-10 >> 1 = {b >> 1}")  # -5
注意：Python没有直接的无符号右移运算符，但可以通过掩码模拟
假设32位整数
print(f"-10 >>> 1 (simulated) = {-10 >> 1 & 0xFFFFFFFF}")